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Question Number 157453 by MathSh last updated on 23/Oct/21

Answered by MJS_new last updated on 23/Oct/21

$$(x+2)(x^2+1)(x^2+x+6)(x^2-x-1)=0$$$$x=-2\vee x=\frac{1\pm \sqrt{5}}{2}\vee x=\pm \mathrm{i}\vee x=-\frac{1\pm \sqrt{23}\mathrm{i}}{2}$$

Commented by MathSh last updated on 23/Oct/21

$$\mathrm{Thank}\mathrm{you}\mathrm{so}\mathrm{much}\mathrm{dear}\mathbf{Ser}$$$$\mathrm{Can}\mathrm{you}\mathrm{specify}\mathrm{where}\mathrm{it}\mathrm{came}\mathrm{from}\mathrm{in}$$$$\mathrm{detail}$$

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