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Question Number 157884 by HongKing last updated on 29/Oct/21
1sin(10°)−4sin(70°)=?
Answered by tounghoungko last updated on 29/Oct/21
1sin10°−4(32cos10°+12sin10°)=1sin10°−23cos10°−2sin10°=1−23sin10°cos10°−2sin210°sin10°=1−3sin20°−2(12−12cos20°)sin10°=cos20°−3sin20°sin10°=2(12cos20°−32sin20°)sin10°=2cos80°sin10°=2.
Commented by HongKing last updated on 29/Oct/21
alotthankyousir
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