Question Number 157935 by VIDDD last updated on 30/Oct/21
$$\:\mathrm{Evaluate}\:\boldsymbol{\mathrm{A}}=\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\left(\mathrm{tan}\frac{\mathrm{k}\pi}{\mathrm{2n}}\right) \\ $$
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Question Number 157935 by VIDDD last updated on 30/Oct/21 | ||
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$$\:\mathrm{Evaluate}\:\boldsymbol{\mathrm{A}}=\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\left(\mathrm{tan}\frac{\mathrm{k}\pi}{\mathrm{2n}}\right) \\ $$ | ||