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Question Number 157957 by HongKing last updated on 30/Oct/21

Commented by MJS_new last updated on 31/Oct/21

$$1\mathrm{equation};4\mathrm{variables}\Rightarrow \mathrm{no}\mathrm{unique}\mathrm{solution}$$

Commented by HongKing last updated on 31/Oct/21

$$\mathrm{how}\mathrm{dear}\mathbf{S}\mathrm{er}...$$

Commented by MJS_new last updated on 31/Oct/21

$$\mathrm{you}\mathrm{are}\mathrm{free}\mathrm{to}\mathrm{choose}b,c,d\mathrm{and}\mathrm{then}\mathrm{solve}$$$$\mathrm{for}a$$$$b=c=d=0\Rightarrow a=\frac{-1\pm \sqrt{65}}{4}$$$$b=c=d=1\Rightarrow a=\frac{-397\pm \sqrt{51241}}{96}$$$$b=17c=-3d=0\Rightarrow a=\frac{-119\pm \sqrt{9901}}{10}$$$$...$$

Answered by mr W last updated on 30/Oct/21

$$\frac{1}{a+2}=a\Rightarrow a^2+2a-1=0\Rightarrow a=\frac{-2\pm \sqrt{8}}{2}$$$$\frac{1}{b+3}=b\Rightarrow b^2+3b-1=0\Rightarrow b=\frac{-3\pm \sqrt{13}}{2}$$$$\frac{1}{c+5}=c\Rightarrow c^2+5c-1=0\Rightarrow c=\frac{-5\pm \sqrt{29}}{2}$$$$\frac{1}{d+7}=d\Rightarrow d^2+7d-1=0\Rightarrow d=\frac{-7\pm \sqrt{53}}{2}$$

Commented by HongKing last updated on 30/Oct/21

$$\mathrm{Thank}\mathrm{you}\mathrm{dear}\mathbf{S}\mathrm{er}$$$$\mathrm{But}\mathrm{please}\mathrm{check}\mathrm{again}$$

Commented by mr W last updated on 30/Oct/21

$$theremightbeothersolutions.$$$$ifyouknowthesolution,please$$$$share.$$

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