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Question Number 157970 by zainaltanjung last updated on 30/Oct/21

Find the neext number for this  sequence below   1). 1,  3, 6, 10, 15....  2). 1, 5 ,14 ,30,  55 ....  3). 1,7,17,31, 49 ....  4).  4, 13,28, 49,74...  5).  1,8,27,64,125....

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{neext}\:\mathrm{number}\:\mathrm{for}\:\mathrm{this} \\ $$$$\mathrm{sequence}\:\mathrm{below}\: \\ $$$$\left.\mathrm{1}\right).\:\mathrm{1},\:\:\mathrm{3},\:\mathrm{6},\:\mathrm{10},\:\mathrm{15}.... \\ $$$$\left.\mathrm{2}\right).\:\mathrm{1},\:\mathrm{5}\:,\mathrm{14}\:,\mathrm{30},\:\:\mathrm{55}\:.... \\ $$$$\left.\mathrm{3}\right).\:\mathrm{1},\mathrm{7},\mathrm{17},\mathrm{31},\:\mathrm{49}\:.... \\ $$$$\left.\mathrm{4}\right).\:\:\mathrm{4},\:\mathrm{13},\mathrm{28},\:\mathrm{49},\mathrm{74}... \\ $$$$\left.\mathrm{5}\right).\:\:\mathrm{1},\mathrm{8},\mathrm{27},\mathrm{64},\mathrm{125}.... \\ $$$$ \\ $$

Answered by MathsFan last updated on 30/Oct/21

1) 21

$$\left.\mathrm{1}\right)\:\mathrm{21} \\ $$$$ \\ $$

Answered by MJS_new last updated on 31/Oct/21

1) 1 3 6 10 15 21          2  3 4   5   6  2) 1 5 14 30 55 91          4 9  16 25 36 (=n^2 )  3) 1 7 17 31 49 71         6 10 14 18 22            4   4    4   4  4) 4 13 28 49 76 109  (typo?)         9   15  21 27 33            6     6    6   6  5) 1 8 27 64 125 216 (=n^3 )

$$\left.\mathrm{1}\right)\:\mathrm{1}\:\mathrm{3}\:\mathrm{6}\:\mathrm{10}\:\mathrm{15}\:\mathrm{21} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{2}\:\:\mathrm{3}\:\mathrm{4}\:\:\:\mathrm{5}\:\:\:\mathrm{6} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{1}\:\mathrm{5}\:\mathrm{14}\:\mathrm{30}\:\mathrm{55}\:\mathrm{91} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{4}\:\mathrm{9}\:\:\mathrm{16}\:\mathrm{25}\:\mathrm{36}\:\left(={n}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{3}\right)\:\mathrm{1}\:\mathrm{7}\:\mathrm{17}\:\mathrm{31}\:\mathrm{49}\:\mathrm{71} \\ $$$$\:\:\:\:\:\:\:\mathrm{6}\:\mathrm{10}\:\mathrm{14}\:\mathrm{18}\:\mathrm{22} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{4}\:\:\:\mathrm{4}\:\:\:\:\mathrm{4}\:\:\:\mathrm{4} \\ $$$$\left.\mathrm{4}\right)\:\mathrm{4}\:\mathrm{13}\:\mathrm{28}\:\mathrm{49}\:\mathrm{76}\:\mathrm{109}\:\:\left(\mathrm{typo}?\right) \\ $$$$\:\:\:\:\:\:\:\mathrm{9}\:\:\:\mathrm{15}\:\:\mathrm{21}\:\mathrm{27}\:\mathrm{33} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{6}\:\:\:\:\:\mathrm{6}\:\:\:\:\mathrm{6}\:\:\:\mathrm{6} \\ $$$$\left.\mathrm{5}\right)\:\mathrm{1}\:\mathrm{8}\:\mathrm{27}\:\mathrm{64}\:\mathrm{125}\:\mathrm{216}\:\left(={n}^{\mathrm{3}} \right) \\ $$

Commented by zainaltanjung last updated on 15/Oct/22

good job brother

$$\mathrm{good}\:\mathrm{job}\:\mathrm{brother} \\ $$

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