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Question Number 157981 by zainaltanjung last updated on 30/Oct/21

$$\mathrm{How}\mathrm{much}\mathrm{the}\mathrm{long}\mathrm{of}\mathrm{the}\mathrm{diagonal}$$$$\mathrm{space},\mathrm{if}\mathrm{total}\mathrm{area}\mathrm{of}\mathrm{a}\mathrm{cube}\mathrm{is}$$$$216{\mathrm{cm}}^2.$$

Answered by cherokeesay last updated on 30/Oct/21

$$theareaofonefaceofcube:$$$$216\mathbf{÷}6=36{cm}^2$$$$(a=6cm)isasideofsquare.$$$$disadiagonal$$$$d^2=a^2+{\left(a\sqrt{2}\right)}^2\Rightarrow$$$$d=\sqrt{a^2+2a^2}=a\sqrt{3}=6\times 1,732=10,392cm$$$$$$

Commented by zainaltanjung last updated on 30/Oct/21

$$\mathrm{Ok}.{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{true}\mathrm{sir}.\mathrm{good}\mathrm{job}$$

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