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Question Number 157982 by tounghoungko last updated on 30/Oct/21

 (3x^2 −4xy+y^2 −3y)dx+(2xy−2x^2 +6y^2 +3x)dy=0

$$\:\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{xy}+{y}^{\mathrm{2}} −\mathrm{3}{y}\right){dx}+\left(\mathrm{2}{xy}−\mathrm{2}{x}^{\mathrm{2}} +\mathrm{6}{y}^{\mathrm{2}} +\mathrm{3}{x}\right){dy}=\mathrm{0} \\ $$

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