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Question Number 158037 by Tawa11 last updated on 30/Oct/21

$$\left(1\right)\underset{\mathrm{z}\to -\mathrm{i}}{\lim }\frac{\mathrm{z}-\mathrm{i}}{{\mathrm{z}}^2+1}$$$$\left(2\right)\underset{\mathrm{z}\to -\mathrm{i}}{\lim }\frac{\mathrm{z}+\mathrm{i}}{{\mathrm{z}}^2+1}$$$$\left(3\right)\underset{\mathrm{z}\to \mathrm{i}}{\lim }\frac{{2\mathrm{z}}^2-\mathrm{zi}+1}{\mathrm{z}-\mathrm{i}}$$

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