Can we reach to (m/((m−1)s)) + ((m+1)/(ms^2 )) from ((ms+m(m+1))/(s(m−s))) ??


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Question Number 158191 by ghakhan88 last updated on 31/Oct/21

$C a n w e r e a c h t o \frac{m}{(m - 1) s} + \frac{m + 1}{{m s}^{2}} f r o m$ $\frac{m s + m (m + 1)}{s (m - s)} ? ?$
Commented by Rasheed.Sindhi last updated on 01/Nov/21

$T {h e y}^{'} r e n o t e q u a l e v e n!$ $f o r m = 2 & s = 1 t h e y h a v e d i f f e r e n t$ $v a l u e s .$ $\frac{m}{(m - 1) s} + \frac{m + 1}{{m s}^{2}} \overset{?}{=} \frac{m s + m (m + 1)}{s (m - s)}$ $\frac{2}{(2 - 1) (1)} + \frac{2 + 1}{2 (1^{2})} \overset{?}{=} \frac{2 (1) + 2 (2 + 1)}{1 (2 - 1)}$ $\frac{2}{1} + \frac{3}{2} \overset{?}{=} \frac{2 + 2 (3)}{2 - 1}$ $\frac{7}{2} \overset{?}{=} \frac{2 + 6}{1}$ $\frac{7}{2} \neq 8$
	Answered by MJS_new last updated on 31/Oct/21

	$no$
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