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Question Number 158274 by HongKing last updated on 01/Nov/21

$$\mathrm{Solve}\mathrm{for}\mathrm{complex}\mathrm{numbers}:$$$${\mathrm{x}}^4+(1+\mathbf{i}){\mathbf{x}}^3+2{\mathbf{ix}}^2+(\mathbf{i}-1)\mathbf{x}-1=0$$$$$$

Answered by mindispower last updated on 01/Nov/21

$$x=-1,solution$$$$(x+1)(x^3+{ix}^2+ix-1)$$$$(x+1)(x+i)(x^2+i)$$$$(x+1)(x+i)(x-e^{-\frac{i\pi }{4}})(x-e^{\frac{3i\pi }{4}})$$

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