x;y;z>0 Solve for real numbers: { ((x^3 + y^3 + z^3 + 3∙((x)^(1/3) + (y)^(1/3) + (z)^(1/3) ) = 12)),((x∙y∙z = 1)) :}


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Question Number 158363 by HongKing last updated on 03/Nov/21
$x;y;z>0 Solve for real numbers: { ((x^3 + y^3 + z^3 + 3∙((x)^(1/3) + (y)^(1/3) + (z)^(1/3) ) = 12)),((x∙y∙z = 1)) :}$
$x; y; z > 0$ $Solve for real numbers :$ ${\begin{cases} x^{3} + y^{3} + z^{3} + 3 \cdot (\sqrt[3]{x} + \sqrt[3]{y} + \sqrt[3]{z}) = 12 \\ x \cdot y \cdot z = 1 \end{cases}$
	Answered by GuruBelakangPadang last updated on 03/Nov/21

	$s i m e t r i c e : x = y = z = 1$
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