Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 158417 by LEKOUMA last updated on 03/Nov/21

z^3 −(7+6i)z^2 +3(1+9i)z+2(7−9i)=0  Resolve the equation (E) sachet that   the stop image  one any solution behoves  thru the righ t equation y=x

$${z}^{\mathrm{3}} −\left(\mathrm{7}+\mathrm{6}{i}\right){z}^{\mathrm{2}} +\mathrm{3}\left(\mathrm{1}+\mathrm{9}{i}\right){z}+\mathrm{2}\left(\mathrm{7}−\mathrm{9}{i}\right)=\mathrm{0} \\ $$$${Resolve}\:{the}\:{equation}\:\left({E}\right)\:{sachet}\:{that}\: \\ $$$${the}\:{stop}\:{image}\:\:{one}\:{any}\:{solution}\:{behoves} \\ $$$${thru}\:{the}\:{righ}\:{t}\:{equation}\:{y}={x} \\ $$

Answered by MJS_new last updated on 03/Nov/21

I don′t understand the meaning of your text  but I can solve the equation for z  z_1 =4+2i  z_2 =1+i  z_3 =2+3i

$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{understand}\:\mathrm{the}\:\mathrm{meaning}\:\mathrm{of}\:\mathrm{your}\:\mathrm{text} \\ $$$$\mathrm{but}\:\mathrm{I}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{for}\:{z} \\ $$$${z}_{\mathrm{1}} =\mathrm{4}+\mathrm{2i} \\ $$$${z}_{\mathrm{2}} =\mathrm{1}+\mathrm{i} \\ $$$${z}_{\mathrm{3}} =\mathrm{2}+\mathrm{3i} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com