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Question Number 158735 by Ashraful Islam last updated on 08/Nov/21

Commented by Ashraful Islam last updated on 08/Nov/21

hello , how is it infinity ? anyone can explain please .

Commented by mnjuly1970 last updated on 08/Nov/21

$$$$$${lim}_{h\to 0^{-}}\frac{-2h+6}{h}={lim}_{x\to 0^{-}}\frac{-2h}{h}+{lim}_{h\to 0^{-}}\frac{6}{h}$$$$=-2+\frac{6}{0^{-}}=-2+(-\mathrm{\infty })=-\mathrm{\infty }$$

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