Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 158768 by EbrimaDanjo last updated on 08/Nov/21

$$$$$$\mathrm{evaluate}$$$$\int 2\mathrm{x}\sqrt{4\mathrm{x}-5}\mathrm{dx}$$

Answered by MJS_new last updated on 08/Nov/21

$$\int 2x\sqrt{4x-5}dx=?$$$$\mathrm{without}\mathrm{substitution}:$$$$\frac{d}{dx}\left[(ax+b){(4x-5)}^{3/2}\right]=(10ax-5a+6b)\sqrt{4x-5}$$$$\Rightarrow$$$$10ax-5a+6b=2x$$$$\Rightarrow$$$$a=\frac{1}{5}\wedge b=\frac{1}{6}$$$$\Rightarrow$$$$\int 2x\sqrt{4x-5}dx=(\frac{x}{5}+\frac{1}{6}){(4x-5)}^{3/2}+C$$

Commented by EbrimaDanjo last updated on 08/Nov/21

$$\mathrm{thanks}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com