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Question Number 158996 by HongKing last updated on 11/Nov/21

Prove that  2017^(2017)   can be written  as sum of eight perfect cubes.

$$\mathrm{Prove}\:\mathrm{that}\:\:\mathrm{2017}^{\mathrm{2017}} \:\:\mathrm{can}\:\mathrm{be}\:\mathrm{written} \\ $$$$\mathrm{as}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{eight}\:\mathrm{perfect}\:\mathrm{cubes}. \\ $$$$ \\ $$

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