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Question Number 159021 by Abdissalammjr last updated on 11/Nov/21

Answered by mkam last updated on 11/Nov/21

$$$$$$\frac{dy}{dx}-\frac{2x}{x+4}y=-0.4$$$$$$$$p\left(x\right)=-\frac{2x}{x+4},Q\left(x\right)=-0.4$$$$$$$$(i.f)=e^{\int p\left(x\right)dx}=e^{\int -\frac{2x}{x+4}dx}=e^{-2\int (1-\frac{4}{x+4})dx}=e^{-2x+ln{(x+4)}^8}={(x+4)}^8.e^{-2x}$$$$$$$$y=\frac{\int (i.f).Q\left(x\right)dx}{(i.f)}=\frac{-0.4\int {(x+4)}^8.e^{-2x}dx}{{(x+4)}^8.e^{-2x}}$$$$$$$$$$$$nowcompletesir$$

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