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Question Number 159030 by cortano last updated on 12/Nov/21

$${\left(\arcsin \left(\cos 93°\right)\right)}^2=?$$

Answered by mr W last updated on 12/Nov/21

$$\cos 93°=-\sin 3°=-\sin \left(\frac{\pi }{60}\right)$$$$arcsin\left(\cos 93°\right)=arcsin(-\sin \frac{\pi }{60})=-\frac{\pi }{60}$$$${\left(arcsin\left(\cos 93°\right)\right)}^2={(-\frac{\pi }{60})}^2=\frac{{\pi }^2}{3600}$$

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