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Question Number 159135 by cherokeesay last updated on 13/Nov/21

Commented by Rasheed.Sindhi last updated on 13/Nov/21

$I^{'} v e n o w u n d e r s t o o d c o m p l e t e l y$ $a l t h o u g h d i f f i c u l t l y .$ $I w a n t t o s a y o n l y t h a t t h e a n s w e r$ $s h o u l d b e s o m e w h a t m o r e d e t a i l e d$ $i n o r d e r t h a t t h e p e r s o n s w h o a r e$ $n o t s h a r p e n o u g h l i k e m e a l s o c a n u n d e r -$ $s t a n d e a s i l y . T h e d i a g r a m i s o k .$
Commented by Rasheed.Sindhi last updated on 13/Nov/21

$\lor \cap i \subset\in!$
Commented by Rasheed.Sindhi last updated on 13/Nov/21

$Difficult to understand due to$ $few steps .$
Commented by cherokeesay last updated on 13/Nov/21

$j u s t f o l l o w t h e s e s t e p s b y t a k i n g a l o o k$ $a t t h e d i a g r a m .$
	Answered by ajfour last updated on 13/Nov/21

	$l e t o u t e r r a d i u s = 2 \Rightarrow r_{2} = 1$ $r_{1} = r$ ${(2 - r)}^{2} - r^{2} = {(1 + r)}^{2} - {(1 - r)}^{2}$ $\Rightarrow 4 - 4 r = 4 r$ $\Rightarrow r = 1 / 2$ $% a r e a = \frac{1 - (\frac{1}{2} + \frac{1}{4})}{1} \times 100 = 25$
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