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Question Number 159325 by mnjuly1970 last updated on 15/Nov/21

        # Trigonometry#         solve (   Equation)              sin((x/2) ) − 2sin ((x/3) )= 0

You can't use 'macro parameter character #' in math modesolve(Equation)sin(x2)2sin(x3)=0

Commented by Ar Brandon last updated on 15/Nov/21

x=12πn±12arctan((√((5/7)+((4(√2))/7))))

x=12πn±12arctan(57+427)

Answered by mr W last updated on 15/Nov/21

sin (((3x)/6))−2sin (((2x)/6))=0  let t=(x/6)  sin (3t)−2sin (2t)=0  sin t (3−4 sin^2  t)−4sin t cos t=0  sin t (4 cos^2  t−4 cos t−1)=0  sin t=0 ⇒t=kπ ⇒x=6kπ  4 cos^2  t−4 cos t−1=0  cos t=((1±(√2))/2)=−(((√2)−1)/2)  (+ rejected)  ⇒t=(2k+1)π±cos^(−1) (((√2)−1)/2)  ⇒x=6(2k+1)π±6 cos^(−1) (((√2)−1)/2)

sin(3x6)2sin(2x6)=0lett=x6sin(3t)2sin(2t)=0sint(34sin2t)4sintcost=0sint(4cos2t4cost1)=0sint=0t=kπx=6kπ4cos2t4cost1=0cost=1±22=212(+rejected)t=(2k+1)π±cos1212x=6(2k+1)π±6cos1212

Commented by mnjuly1970 last updated on 16/Nov/21

very nice sir W

verynicesirW

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