Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 159355 by mnjuly1970 last updated on 16/Nov/21

Answered by mr W last updated on 16/Nov/21

radius of small circle r=(b/2)  (b/2)×(b/2)=(a−(b/2))(a+(b/2))  (b^2 /4)=a^2 −(b^2 /4)  (b^2 /2)=a^2   ⇒(b/a)=(√2)

radiusofsmallcircler=b2b2×b2=(ab2)(a+b2)b24=a2b24b22=a2ba=2

Commented by mr W last updated on 16/Nov/21

Commented by Tawa11 last updated on 16/Nov/21

Great sir

Greatsir

Commented by mnjuly1970 last updated on 16/Nov/21

  god keep you master W

godkeepyoumasterW

Terms of Service

Privacy Policy

Contact: info@tinkutara.com