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Question Number 159690 by 0731619 last updated on 20/Nov/21

Answered by MJS_new last updated on 21/Nov/21

$$\mathrm{very}\mathrm{obviously}\mathrm{the}\mathrm{limit}\mathrm{is}+\mathrm{\infty }$$$$\mathrm{check}\mathrm{for}x=5$$$$\frac{5^{5!}}{{(5!)}^5}=\frac{5^{120}}{{120}^5}=\frac{\approx {10}^{84}}{\approx {10}^{10}}$$

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