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Question Number 159716 by mathocean1 last updated on 20/Nov/21

$$Showthat▽r^n={nr}^{n-2}r$$

Answered by puissant last updated on 20/Nov/21

$$▽r^n={nr}^{n-1}={nr}^{n-2}\times r$$

Commented by mathocean1 last updated on 23/Nov/21

thanks.

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