Given the curve y=x^4 +3x^3 −6x^2 −3x determine for which value of α the tangent to the curve from point P(α,0) is maximum.


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Question Number 159874 by tounghoungko last updated on 22/Nov/21

$G i v e n t h e c u r v e y = x^{4} + 3 x^{3} - 6 x^{2} - 3 x$ $d e t e r m i n e f o r w h i c h v a l u e$ $o f α t h e t a n g e n t t o t h e c u r v e$ $f r o m p o i n t P (α, 0) i s m a x i m u m .$
Commented by mr W last updated on 22/Nov/21

$w h a t d o y o u m e a n w i t h ‘ ‘ t h e t a n g e n t$ $t o t h e c u r v e i s {m a x i m u m}^{″} ?$
Commented by tounghoungko last updated on 22/Nov/21

$t h e t a n g e n t w i t h s l o p e m a x i m u m$
Commented by mr W last updated on 22/Nov/21

$n o s o l u t i o n!$ $s i n c e w h e n x \to + \infty, y^{'} \to + \infty$
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