Resolve 1. u_n −3u_(n−1) =12((3/4))^n 2. u_n =2u_(n−1) +5cos (((nΠ)/3)), u_o =1 3. u_n =u_(n−1) −u_(n−2) +2sin (((nΠ)/3)) with u_o =1, u


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Question Number 159881 by LEKOUMA last updated on 22/Nov/21

$R e s o l v e$ $1 . u_{n} - 3 u_{n - 1} = 12 {(\frac{3}{4})}^{n}$ $2 . u_{n} = 2 u_{n - 1} + 5 \cos (\frac{n Π}{3}), u_{o} = 1$ $3 . u_{n} = u_{n - 1} - u_{n - 2} + 2 \sin (\frac{n Π}{3})$ $w i t h u_{o} = 1, u_{1} = 2$
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