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Question Number 159906 by qaz last updated on 22/Nov/21

$$\underset{\mathrm{x}\to 0}{\lim }\frac{\underset{\mathrm{n}}{\underbrace{\tan \tan \tan ...\tan \mathrm{x}}}-\underset{\mathrm{n}}{\underbrace{\sin \sin \sin ...\sin \mathrm{x}}}}{{\mathrm{x}}^2}=?$$

Answered by kaivan.ahmadi last updated on 24/Nov/21

$$\sim lim\frac{\frac{x^3}{2}}{x^2}=lim\frac{x}{2}=0$$

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