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Question Number 16047 by vpawarksp@gmail.com last updated on 17/Jun/17

number of real solution of equation    a^(2008)  +  b^(2008)   = 2008ab−2006

$${number}\:{of}\:{real}\:{solution}\:{of}\:{equation}\:\:\:\:{a}^{\mathrm{2008}} \:+\:\:{b}^{\mathrm{2008}} \:\:=\:\mathrm{2008}{ab}−\mathrm{2006}\:\:\:\:\:\:\:\:\: \\ $$

Commented by Tinkutara last updated on 17/Jun/17

You can verify that a = b = 1 satisfy  the equation.

$$\mathrm{You}\:\mathrm{can}\:\mathrm{verify}\:\mathrm{that}\:{a}\:=\:{b}\:=\:\mathrm{1}\:\mathrm{satisfy} \\ $$$$\mathrm{the}\:\mathrm{equation}. \\ $$

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