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Question Number 160806 by HongKing last updated on 06/Dec/21

Answered by MJS_new last updated on 06/Dec/21

$$A=0\vee A=5$$$$$$$$y=A-x$$$$x^3+{(A-x)}^3=5x(A-x)$$$$(3A+5)x^2-A(3A+5)x+A^3=0$$$$x=\frac{A}{2}\pm \frac{A\sqrt{5-A}}{2\sqrt{3A+5}}$$$$\mathrm{one}\mathrm{solution}\mathrm{if}\frac{A\sqrt{5-A}}{2\sqrt{3A+5}}=0\Rightarrow A=0\vee A=5$$

Commented by HongKing last updated on 06/Dec/21

$$\mathrm{cool}\mathrm{thank}\mathrm{you}\mathrm{so}\mathrm{much}\mathrm{my}\mathrm{dear}\mathrm{Sir}$$

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