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Question Number 160825 by qaz last updated on 07/Dec/21

$$\underset{\mathrm{n}\to \mathrm{\infty }}{\lim }{\left[{\int }_0^1{(1+\sin \frac{\pi \mathrm{t}}{2})}^{\mathrm{n}}\mathrm{dt}\right]}^{\frac{1}{\mathrm{n}}}=?$$

Answered by mnjuly1970 last updated on 07/Dec/21

$$answer:\mathrm{\Omega }:={sup}_{[0,1]}(1+sin\left(\frac{\pi t}{2}\right))$$$$\underset{iscompactset}{\stackrel{[0,1]}{=}}2$$

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