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Question Number 160832 by cortano last updated on 07/Dec/21

$$\sqrt{2021-2\sqrt{2021-2\sqrt{2021-2\mathrm{x}}}}=\mathrm{x}$$$$\mathrm{x}=?$$

Answered by Raxreedoroid last updated on 07/Dec/21

$$x=\sqrt{2021-2x}$$$$x^2=2021-2x$$$$x^2+2x-2021=0$$$$x=-1\pm \sqrt{2022}$$

Commented by mr W last updated on 07/Dec/21

$$x=\sqrt{....}>0$$$$\Rightarrow onlyx=-1+\sqrt{2022}isroot.$$

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