Question Number 16092 by Tinkutara last updated on 17/Jun/17 | ||
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:{x}\:\in\:\left[\mathrm{0},\:\mathrm{2}\pi\right] \\ $$ $$\mathrm{which}\:\mathrm{satisfy}\:\mathrm{sin}\:{x}\:>\:\mathrm{cos}\:{x}. \\ $$ $$\left(\mathrm{1}\right)\:\left(\frac{\pi}{\mathrm{4}},\:\frac{\mathrm{3}\pi}{\mathrm{4}}\right)\:\cup\:\left(\frac{\mathrm{5}\pi}{\mathrm{4}},\:\mathrm{2}\pi\right) \\ $$ $$\left(\mathrm{2}\right)\:\left(\mathrm{0},\:\frac{\pi}{\mathrm{4}}\right)\:\cup\:\left(\frac{\mathrm{5}\pi}{\mathrm{4}},\:\mathrm{2}\pi\right) \\ $$ $$\left(\mathrm{3}\right)\:\left(\frac{\pi}{\mathrm{4}},\:\frac{\mathrm{5}\pi}{\mathrm{4}}\right) \\ $$ $$\left(\mathrm{4}\right)\:\left(\mathrm{0},\:\frac{\mathrm{3}\pi}{\mathrm{4}}\right)\:\cup\:\left(\frac{\mathrm{5}\pi}{\mathrm{4}},\:\mathrm{2}\pi\right) \\ $$ | ||
Commented byTinkutara last updated on 19/Jun/17 | ||
$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$ | ||
Commented bymrW1 last updated on 17/Jun/17 | ||
$$\left(\mathrm{3}\right) \\ $$ | ||
Commented byTinkutara last updated on 18/Jun/17 | ||
$$\mathrm{Can}\:\mathrm{you}\:\mathrm{explain}\:\mathrm{please}? \\ $$ | ||
Commented bymrW1 last updated on 18/Jun/17 | ||
$$\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}>\mathrm{0} \\ $$ $$\sqrt{\mathrm{2}}\left(\frac{\mathrm{1}}{\sqrt{\mathrm{2}}}\mathrm{sin}\:\mathrm{x}−\frac{\mathrm{1}}{\sqrt{\mathrm{2}}}\mathrm{cos}\:\mathrm{x}\right)>\mathrm{0} \\ $$ $$\sqrt{\mathrm{2}}\mathrm{sin}\:\left(\mathrm{x}−\frac{\pi}{\mathrm{4}}\right)>\mathrm{0} \\ $$ $$\mathrm{sin}\:\left(\mathrm{x}−\frac{\pi}{\mathrm{4}}\right)>\mathrm{0} \\ $$ $$\Rightarrow\mathrm{0}<\mathrm{x}−\frac{\pi}{\mathrm{4}}<\pi \\ $$ $$\frac{\pi}{\mathrm{4}}<\mathrm{x}<\frac{\mathrm{5}\pi}{\mathrm{4}} \\ $$ | ||
Commented bymrW1 last updated on 18/Jun/17 | ||
$$\mathrm{or}\:\mathrm{you}\:\mathrm{just}\:\mathrm{have}\:\mathrm{a}\:\mathrm{look}\:\mathrm{at}\:\mathrm{the}\:\mathrm{graphs} \\ $$ $$\mathrm{from}\:\mathrm{sin}\:\mathrm{x}\:\mathrm{and}\:\mathrm{cos}\:\mathrm{x}. \\ $$ | ||