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Question Number 161311 by CM last updated on 15/Dec/21

Differentiate y=sin xy

Differentiatey=sinxy

Answered by mr W last updated on 15/Dec/21

(dy/dx)=cos (xy)(y+x(dy/dx))  ⇒(dy/dx)=((y cos (xy))/(1−x cos (xy)))

dydx=cos(xy)(y+xdydx)dydx=ycos(xy)1xcos(xy)

Commented by CM last updated on 16/Dec/21

Thank you sir

Thankyousir

Answered by 1549442205PVT last updated on 16/Dec/21

we assume that y is a function of x.Then  y′=cosxy.(y+xy′)⇒y′(1−xcosxy)=ycosxy  ⇒y′=((ycosxy)/(1−xcosxy))

weassumethatyisafunctionofx.Theny=cosxy.(y+xy)y(1xcosxy)=ycosxyy=ycosxy1xcosxy

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