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Question Number 16139 by Tinkutara last updated on 18/Jun/17

Path of the bomb released from an  aeroplane moving with uniform  velocity at certain height as observed  by the pilot is  (a) a straight line  (b) a parabola  (c) a circle  (d) none of the above

$$\mathrm{Path}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bomb}\:\mathrm{released}\:\mathrm{from}\:\mathrm{an} \\ $$$$\mathrm{aeroplane}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{uniform} \\ $$$$\mathrm{velocity}\:\mathrm{at}\:\mathrm{certain}\:\mathrm{height}\:\mathrm{as}\:\mathrm{observed} \\ $$$$\mathrm{by}\:\mathrm{the}\:\mathrm{pilot}\:\mathrm{is} \\ $$$$\left({a}\right)\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line} \\ $$$$\left({b}\right)\:\mathrm{a}\:\mathrm{parabola} \\ $$$$\left({c}\right)\:\mathrm{a}\:\mathrm{circle} \\ $$$$\left({d}\right)\:\mathrm{none}\:\mathrm{of}\:\mathrm{the}\:\mathrm{above} \\ $$

Answered by mrW1 last updated on 18/Jun/17

(a)

$$\left(\mathrm{a}\right) \\ $$

Commented by Tinkutara last updated on 18/Jun/17

Can you explain please?

$$\mathrm{Can}\:\mathrm{you}\:\mathrm{explain}\:\mathrm{please}? \\ $$

Commented by mrW1 last updated on 18/Jun/17

bomb:  x_b =ut  y_b =−(1/2)gt^2   pilot:  x_p =ut  y_p =0  bomb seen from pilot:  x′=x_b −x_p =0  y′=y_b −y_p =−(1/2)gt^2   that means seen from pilot the bomb  is just in free fall.

$$\mathrm{bomb}: \\ $$$$\mathrm{x}_{\mathrm{b}} =\mathrm{ut} \\ $$$$\mathrm{y}_{\mathrm{b}} =−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}^{\mathrm{2}} \\ $$$$\mathrm{pilot}: \\ $$$$\mathrm{x}_{\mathrm{p}} =\mathrm{ut} \\ $$$$\mathrm{y}_{\mathrm{p}} =\mathrm{0} \\ $$$$\mathrm{bomb}\:\mathrm{seen}\:\mathrm{from}\:\mathrm{pilot}: \\ $$$$\mathrm{x}'=\mathrm{x}_{\mathrm{b}} −\mathrm{x}_{\mathrm{p}} =\mathrm{0} \\ $$$$\mathrm{y}'=\mathrm{y}_{\mathrm{b}} −\mathrm{y}_{\mathrm{p}} =−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}^{\mathrm{2}} \\ $$$$\mathrm{that}\:\mathrm{means}\:\mathrm{seen}\:\mathrm{from}\:\mathrm{pilot}\:\mathrm{the}\:\mathrm{bomb} \\ $$$$\mathrm{is}\:\mathrm{just}\:\mathrm{in}\:\mathrm{free}\:\mathrm{fall}. \\ $$

Commented by Tinkutara last updated on 18/Jun/17

Thanks Sir!

$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$

Answered by ajfour last updated on 18/Jun/17

Commented by mrW1 last updated on 18/Jun/17

what for a nice picture!

$$\mathrm{what}\:\mathrm{for}\:\mathrm{a}\:\mathrm{nice}\:\mathrm{picture}! \\ $$

Commented by Tinkutara last updated on 18/Jun/17

Thanks Sir!

$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$

Commented by ajfour last updated on 18/Jun/17

a good question in reward will do!

$${a}\:{good}\:{question}\:{in}\:{reward}\:{will}\:{do}! \\ $$

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