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Question Number 161408 by mathlove last updated on 17/Dec/21

Commented by som(math1967) last updated on 17/Dec/21

9

9

Answered by behi834171 last updated on 17/Dec/21

12=[Σa][Σ(1/a)]=3+(a/b)+(a/c)+(b/a)+(b/c)+(c/a)+(c/b)= =3+Σ((a^2 +b^2 )/(ab))⇒Σ ((a^2 +b^2 )/(ab))=12−3=9 .■

12=[Σa][Σ1a]=3+ab+ac+ba+bc+ca+cb==3+Σa2+b2ab⇒Σa2+b2ab=12−3=9.◼

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