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Question Number 161410 by saly last updated on 17/Dec/21

Commented by saly last updated on 17/Dec/21

$$Thankyou$$

Commented by saly last updated on 17/Dec/21

$$Doyouhelpme$$

Commented by geron last updated on 17/Dec/21

$$tg\left(\frac{-27\mathrm{\Pi }}{4}\right)=tg(-6\mathrm{\Pi }-\frac{3\mathrm{\Pi }}{4})=tg(-\frac{3\mathrm{\Pi }}{4})=-\frac{sin\left(\frac{3\mathrm{\Pi }}{4}\right)}{cos\left(\frac{3\mathrm{\Pi }}{4}\right)}=$$$$=-\frac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}}=1$$

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