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Question Number 161418 by geron last updated on 17/Dec/21

4^(2021 ) =a^3 +b^3 +c^3 , (a:b:c)⇒ natural numbers

$$\mathrm{4}^{\mathrm{2021}\:} ={a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} ,\:\left({a}:{b}:{c}\right)\Rightarrow\:{natural}\:{numbers} \\ $$

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