Question and Answers Forum

All Questions      Topic List

Set Theory Questions

Previous in All Question      Next in All Question      

Previous in Set Theory      Next in Set Theory      

Question Number 161439 by amin96 last updated on 17/Dec/21

Commented by bobhans last updated on 18/Dec/21

$$\left(\mathrm{Q}2\right)\mathrm{y}=\frac{\mathrm{x}-\psi }{{\mathrm{x}}^2-5\mathrm{x}+6}\Rightarrow {\mathrm{yx}}^2-5\mathrm{yx}+6\mathrm{y}=\mathrm{x}-\psi$$$${\mathrm{yx}}^2-(5\mathrm{y}+1)\mathrm{x}+(6\mathrm{y}+\psi )=0$$$$△⩾0\Rightarrow {25\mathrm{y}}^2+10\mathrm{y}+1-4\mathrm{y}(6\mathrm{y}+\psi )⩾0$$$${\mathrm{y}}^2+(10-4\psi )\mathrm{y}+1⩾0$$$$△<0\Rightarrow 100-80\psi +16{\psi }^2-4<0$$$$16{\psi }^2-80\psi +96<0$$$${\psi }^2-5\psi +6<0$$$$(\psi -3)(\psi -2)<0\Rightarrow 2<\psi <3$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com