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Question Number 161590 by geron last updated on 20/Dec/21
f(x)=11−x+11−1−xf(x)min=?
Answered by cortano last updated on 20/Dec/21
Answered by mr W last updated on 20/Dec/21
0<x<1letx=sin2(45°+θ)with−45°<θ<45°f(x)=11−sin(45°+θ)+11−cos(45°+θ)=11−sin(45°+θ)+11−sin(45°−θ)f(x)min=2×11−12=2(2+2)atθ=0°orx=12
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