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Question Number 161750 by CM last updated on 22/Dec/21

$$differenciatex\sin x\cos x$$

Commented by cortano last updated on 22/Dec/21

$$f\left(x\right)=\frac{1}{2}x\sin 2x$$$$\frac{df}{dx}=\frac{1}{2}(\sin 2x+2x\cos 2x)$$$$=\frac{1}{2}\sin 2x+x\cos 2x$$$$$$

Commented by CM last updated on 22/Dec/21

$$Thankyou$$

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