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Question Number 161760 by cortano last updated on 22/Dec/21
limx→0tanx(1−cosx)23=?
Answered by Ar Brandon last updated on 22/Dec/21
L=limx→0tanx(1−cosx)23=limx→0x+x33x443=43⋅limx→0(x1−43+13x3−43)=43⋅limx→0(1x3+x533)→±∞
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