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Question Number 161914 by mnjuly1970 last updated on 24/Dec/21
If,x2+9y2+4x+18y−23=0thenfindthevalueof,Max(3x+2y).−−−−−−−−−
Answered by mr W last updated on 24/Dec/21
therearemanywaystosolve.seeQ161626.themethodiprefer:x2+9y2+4x+18y−23=0(x+2)2+9(y+1)2=36(x+26)2+(y+12)2=1line3x+2y=kshouldtangentellipse.62×32+22×22=(3×(−2)+2×(−1)−k)262×32+22×22=(k+8)2k=−8±285⇒(3x+2y)min=−8−285⇒(3x+2y)max=−8+285
Commented by mnjuly1970 last updated on 24/Dec/21
thanksalotsirW.
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