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Question Number 161966 by amin96 last updated on 24/Dec/21
∫x27x2dx=?
Answered by Ar Brandon last updated on 25/Dec/21
I=∫x27x2dx=∫x2ex2log7dx=∑∞n=0∫x2(x2log7)nn!dx=∑∞n=0logn7n!(2n+3)x2n+3=x32∑∞n=0(1)nlogn7n!(n+32)x2n=x32∑∞n=0(1)nΓ(n+32)n!Γ(n+52)(x2log7)n=x33∑∞n=0(1)n(32)nn!(52)n(x2log7)n=x332F1(1,32;52;x2log7)
Commented by amin96 last updated on 25/Dec/21
whatisF1??
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