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Question Number 162182 by bobhans last updated on 27/Dec/21
limx→∞(x−x2−3x+2)2022+(x−x2−5)2022x2022=?
Answered by cortano last updated on 27/Dec/21
limx→∞(x−x1−3x−1+2x−2)2022+(x−x1−5x−2)2022x2022=limx→∞(1−1−3x−1+2x−2)2022+(1−1−5x−2)20221=0
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