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Question Number 162187 by mathlove last updated on 27/Dec/21

x^y =9  ((32y))^(1/y) =2x^2          (x,y)=?  sulotion =?

$${x}^{{y}} =\mathrm{9} \\ $$$$\sqrt[{{y}}]{\mathrm{32}{y}}=\mathrm{2}{x}^{\mathrm{2}} \:\:\:\:\:\:\:\:\:\left({x},{y}\right)=? \\ $$$${sulotion}\:=? \\ $$$$ \\ $$

Commented by mr W last updated on 27/Dec/21

i think there is no solution.  try to change x^y =9 to x^y =3, then  solution possible.

$${i}\:{think}\:{there}\:{is}\:{no}\:{solution}. \\ $$$${try}\:{to}\:{change}\:{x}^{{y}} =\mathrm{9}\:{to}\:{x}^{{y}} =\mathrm{3},\:{then} \\ $$$${solution}\:{possible}. \\ $$

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