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Question Number 162229 by Tawa11 last updated on 27/Dec/21

	Answered by mr W last updated on 28/Dec/21

	$u_{X} = s p e e d o f g e a r X$ $t_{X} = t o r q u e o f g e a r X$ $u_{D} = 200 r p m ↷$ $t_{D} = 15 N m$ $u_{C} = \frac{20}{10} \times n_{D} = 2 u_{D} = 400 r p m ↶$ $u_{B} = u_{C} = 400 r p m ↶$ $u_{A} = \frac{20}{10} \times n_{B} = 2 u_{B} = 800 r p m ↷$ $t h e t o r q u e o n t h e g e a r s c a n n o t b e$ $d e t e r m i n e d a c c o r d i n g t o m y$ $u n d e r s t a n d i n g .$ $p l e a s e a s k y o u r t e a c h e r w h a t i s$ $m e a t h e r e!$
	Commented by Tawa11 last updated on 28/Dec/21

	$Thank you sir . I appreciate . God bless you more .$
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