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Question Number 162510 by cortano last updated on 30/Dec/21

  lim_(x→0)  ((7tan x−tan 7x)/(3x)) =?

$$\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{7tan}\:{x}−\mathrm{tan}\:\mathrm{7}{x}}{\mathrm{3}{x}}\:=? \\ $$

Answered by Lordose last updated on 30/Dec/21

L−Hopital′s; ((7sec^2 (x)−7sec^2 (7x))/3) = (0/3) = 0

$$\mathrm{L}−\mathrm{Hopital}'\mathrm{s};\:\frac{\mathrm{7sec}^{\mathrm{2}} \left(\mathrm{x}\right)−\mathrm{7sec}^{\mathrm{2}} \left(\mathrm{7x}\right)}{\mathrm{3}}\:=\:\frac{\mathrm{0}}{\mathrm{3}}\:=\:\mathrm{0} \\ $$

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