Question Number 162673 by mkam last updated on 31/Dec/21
Answered by mr W last updated on 31/Dec/21
$$\left({i}\right)×\mathrm{2}−\left({ii}\right): \\ $$$$−\mathrm{3}{x}=\mathrm{3}{t}+\mathrm{2}\:\Rightarrow{x}=−{t}−\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$−\mathrm{1}+{t}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{{dy}}{{dt}}=\mathrm{2}{t}+\mathrm{1} \\ $$$$\frac{{dy}}{{dt}}={t}+\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\Rightarrow{y}=\frac{{t}^{\mathrm{2}} }{\mathrm{2}}+\frac{\mathrm{4}{t}}{\mathrm{3}}+{C} \\ $$
Commented by mkam last updated on 31/Dec/21
$${put}\:{sir}\:{how}\:{x}\:=\:−\:\frac{\mathrm{2}}{\mathrm{3}}\:{and}\:\frac{{dx}}{{dt}}\:=\:\mathrm{0}\:?\:{can}\:{you}\:{clearly}\:{that}\:{please}\:? \\ $$
Commented by mkam last updated on 31/Dec/21
$${i}\:{think}\:{x}\:=\:−{t}\:−\frac{\mathrm{2}}{\mathrm{3}}\:{not}\:−\:\frac{\mathrm{2}}{\mathrm{3}} \\ $$
Commented by mkam last updated on 31/Dec/21
Commented by mkam last updated on 31/Dec/21
$${this}\:{solution}\:{is}\:{true}\:{or}\:{not}\:? \\ $$
Commented by mr W last updated on 31/Dec/21
$${yes}.\:{i}\:{made}\:{a}\:{mistake}\:{after}\:{a}\:{typo}. \\ $$$${now}\:{it}'{s}\:{correct}. \\ $$
Commented by mkam last updated on 31/Dec/21
$${thank}\:{you}\:{sir} \\ $$