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Question Number 162845 by mkam last updated on 01/Jan/22

Commented by mkam last updated on 01/Jan/22

$$provethis$$

Answered by abdullahhhhh last updated on 01/Jan/22

$$\mathbf{y}=\mathbf{x}+\frac{1}{\mathbf{y}}$$$${\mathbf{y}}^2=\mathbf{xy}+1$$$$2\mathbf{y}\frac{\mathbf{dy}}{\mathbf{dx}}=\mathbf{x}\frac{\mathbf{dy}}{\mathbf{dx}}+\mathbf{y}$$$$\frac{\mathbf{dy}}{\mathbf{dx}}=\frac{\mathbf{y}}{2\mathbf{y}-\mathbf{x}}$$

Commented by peter frank last updated on 02/Jan/22

$$\mathrm{great}$$

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