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Question Number 163110 by ampomahlosotho last updated on 03/Jan/22

Answered by mahdipoor last updated on 03/Jan/22

2^(x−2) =8x⇒(1/(32))2^x =x⇒−(1/(32×ln2))=(−(x/(ln2)))2^((−x)) = (−(x/(ln2)))2^(ln2×((−x)/(ln2))) =(−(x/(ln2)))e^((((−x)/(ln2)))) ⇒ ((−x)/(ln2))=w(−(1/(32.ln2)))⇒x=−ln2w(((−1)/(32.ln2)))

2x−2=8x⇒1322x=x⇒−132×ln2=(−xln2)2(−x)=(−xln2)2ln2×−xln2=(−xln2)e(−xln2)⇒−xln2=w(−132.ln2)⇒x=−ln2w(−132.ln2)

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