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Question Number 163167 by cortano1 last updated on 04/Jan/22

 6^(x+1)  +1 = 8^(x+1) −27^x     x=?

$$\:\mathrm{6}^{{x}+\mathrm{1}} \:+\mathrm{1}\:=\:\mathrm{8}^{{x}+\mathrm{1}} −\mathrm{27}^{{x}} \: \\ $$$$\:{x}=? \\ $$

Answered by MJS_new last updated on 05/Jan/22

x=0∨x=1

$${x}=\mathrm{0}\vee{x}=\mathrm{1} \\ $$

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