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Question Number 163214 by cortano1 last updated on 05/Jan/22

 lim_(x→0)  ((2sin x−2tan x+x^3 )/(6x−2sin 3x−9x^3 )) =?

$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2sin}\:{x}−\mathrm{2tan}\:{x}+{x}^{\mathrm{3}} }{\mathrm{6}{x}−\mathrm{2sin}\:\mathrm{3}{x}−\mathrm{9}{x}^{\mathrm{3}} }\:=? \\ $$

Commented by blackmamba last updated on 05/Jan/22

 L = (5/(81))

$$\:\mathcal{L}\:=\:\frac{\mathrm{5}}{\mathrm{81}} \\ $$

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